The largest 4 digit perfect cube number can be obtained by cubing some natural numbers at random. ⇒ 10*10*10 = 1000 - which is very much less than the largest 4 digit number, which is 9999. ⇒ 15*15*15 = 3375 - It is also very much less than the largest 4 digit number, which is 9999. ⇒ 20*20*20 = 8000 - It is also less than the largest 4 Step by step video, text & image solution for The difference between 6-digit smallest number and 4-digit largest number is: by Maths experts to help you in doubts & scoring excellent marks in Class 6 exams. To find the largest four-digit number with different digits that is divisible by 2, 5, 9, and 11, we can start by considering the divisibility rules for these numbers. For a number to be divisible by 2, its units digit must be an even number. Therefore, the units digit of our four-digit number can only be 0, 2, 4, 6, or 8. We will be using the concepts of prime numbers, factors to solve this. The greatest 4-digit number is 9999. 9999 = 3 × 3 × 11 × 101 [Prime factors are the factors of the given number which are prime.] Thus, the prime factors of the greatest 4-digit number 9999 are 3, 3, 11, 101. NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.5 Any one-digit number (from 1 to 9) multiplied by 10 produces a two-digit number as the outcome. For illustration, 4 x 10 = 40. 11 is the smallest two-digit number with just one digit. 10 is the smallest two-digit number with two separate digits. Thus, the smallest two-digit number is 10. 99 is the largest two-digit number with just one digit. Hence LCM of the largest 2-digit composite number 99 is 1,980. HCF of Largest 2-digit composite numbers: The largest two-digit composite number is 99 and the largest two-digit even number that can be divided by both 3 and 5 is 90. Now, Look for HCF values of 90 and 99. a = 99, b = 90. 99 = 90 × 1 + 9 99 = 90 × 1 + 9. The largest 4-digit number in the number system is 9999. Assuming +1 is added to the number (9999) it becomes a 5-digit number that is 10000 (five-digit number). So 9999 is the biggest 4-digit number in the number system. Largest 4 digit number = 9999 = 9999 + 1 = 10000 ( Which is 5 digit number ) The largest number of four digits exactly divisible by 88 . Concept used. Divisibility and remainder. Calculation. The largest four digit number is 9999. When we divide 9999 by 88 we get 55 as remainder. Substract the ramainder from the Dividend. ⇒ 9999 - 55 = 9944. The number exactly divisible by 88 is 9944 2JpU4.